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Help once more :) please... a circle has the equation 4(x-5)^2+4y^2=4 find the center (h,k) and radius r
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That's not a circle; is it 4y^2?
Assuming it is 4y^2: Formula for a circle is (x-h)^2+(y-k)^2=r^2, so divide both sides by 4 in yours to get (x-5)^2+(y-0)^2=1, so it's center is (5,0), and radius is sqrt(1) = 1
sorry i fixed it :)
@channie2003 Ok, then yeah, my answer above should be good :)
Thank you so much
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@channie2003 Yup, glad to help. All I ask for in return is wishes of good luck on my AP test tomorrow ;)
well I wish you the best of luck on your AP test!!!!
@channie2003 Haha, thank you very much! :)
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