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Mathematics 23 Online
OpenStudy (anonymous):

suppose a runner takes 45 min to run a route at 8mi/h at the beginning of the training season. by the end of training season, she can run the same route in 38 min. what is her speed at the end of the training season? Please Help!! Just Need Steps :)

OpenStudy (anonymous):

distance=rate*time

OpenStudy (anonymous):

plug in the numbers

OpenStudy (anonymous):

find the distance, then use that to find the second rate

OpenStudy (anonymous):

so the distance would be 8mi/h? and the time would be 45 min? right?

OpenStudy (anonymous):

the rate is 8 mi/h

OpenStudy (nurali):

classic d=rt question. so at first she runs d=r(8)t(45/60), which just off the top of my head is 6 miles I believe. use your calculator to double check me on this. using that for the next question 6 miles(d)=x(r)38/60 hours(t), her rate is then 360/38 mi per hour

OpenStudy (anonymous):

|dw:1367992464883:dw| then wht

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