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Why limit sin(7x)/(4x) as x->0 from the left is 7/4?
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\[\lim_{x \rightarrow 0}\frac{ \sin 7x }{ 4x}\]
As \[x \rightarrow 0\] \[\sin (x) \approx x\]
Ezea, sorry, I did not get it.
You could plug in values to the function that are near 0 and see what happens. For instance x = .01, .001, .000001, .0000000001.
Or perhaps look at a picture of a right triangle and put an angle x inside and compare the value to the ratio sin(x).
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Yes I saw on wolfram alpha, but algebrically? How does it work?
No L'Hôpital's Rule.
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