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Mathematics 17 Online
OpenStudy (anonymous):

Please Show Me How To Solve This

OpenStudy (anonymous):

\[\frac{ 5 }{ 2x-3 }=\frac{ 7 }{ 3x }\]

OpenStudy (anonymous):

cross multiply

OpenStudy (anonymous):

cross multiply what?

OpenStudy (anonymous):

i mean do cross multiplication like this 5(3x) = 7(2x-3)

OpenStudy (anonymous):

now perform the multipication

OpenStudy (loser66):

@rizwan_uet add condition, please, something like x != 0 and x!= 3/2

OpenStudy (anonymous):

what where this x! = 0 and x! = 3/2 came from

OpenStudy (anonymous):

@Loser66

OpenStudy (loser66):

!= is not equal. because the whole thing is in denominator, you have to put them in those condition before "cross" them , right? in case after solving, you get exactly x =0, you have to reject that solution.

OpenStudy (loser66):

think of this, what if x =0? or x = 3/2? the equation is undefined, right?

OpenStudy (anonymous):

|dw:1368022187994:dw|

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