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OpenStudy (hunus):
The formula for the difference of two squares says that the difference of two squares is equal to the sum of the two numbers multiplied by their difference.
\[(a^2-b^2)=(a+b)(a-b)\]
\[5^2-7^2=(5-7)(5+7)\]
So that the 5-7 factors cancel
\[\frac{(5-7)(5+7)}{5-7} = 5+7 = 12\]
OpenStudy (anonymous):
wowit seems pretty simple
OpenStudy (hunus):
Yup :)
OpenStudy (anonymous):
it is :) haha
OpenStudy (hunus):
Just try practicing some more. Work some extra problems and if you need help with them ask here :)
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OpenStudy (anonymous):
im not good at algebra 2 what so ever i try and i try but i cant seem to understand it and im a senior in high school
OpenStudy (hunus):
Well whatever it is you need help with, if I'm on just shoot me an @hunus and I'll help
OpenStudy (anonymous):
i'll try to help as much as i can :) haha but i havent had algebra 2 yet