Question

Here are the questions

Answer 1

\[\frac{ \sqrt{1-\sin A} }{ 1+\sin A }=\sec A-\tan A\]

Answer 2

i am sorry but i have no time to repost and repost so i am posting all the questions here in a numbered order, when u answer plz mention the question number 2. \[\frac{ \tan A }{ 1- \cot A } - \frac{ \cot A }{ 1-\tan A} = \sec A cosec A +1\]

Answer 3

3.
\[\frac{ cosA } { 1-tanA }+\frac{sinA} { 1-cotA } =sinA + cosA\]
@Loser66 Plz help me

Answer 4

4.
\[(sinA + cosA) (cotA + tanA)=secA+cosecA\]

Answer 5

@chmvijay @Loser66 @terenzreignz @Frostbite plz help!!!! its really urgent

Answer 6

@aaronq

Answer 7

I did number 4 . go from RHS
sec + csc = 1/ cos + 1/ sin= (sin + cos )/ sin cox
= (sin + cos ) ( 1/ sin cos)
let the first term a side, just the second term ( to save time)
i have the identity cot + tan = cos/ sin + sin/ cos = (cos^2 + sin^2 )/ sin cos = 1/ sin cos
so, 1/ sin cos = cot + tan
replace and combine with the first term above ( sin + cos) (cot + tan ) = sec + csc
such a problem you have!!! harsh one

Answer 8

5.
\[\sin ^{3}-\cos^{3} = (\sin ^{2}-\cos ^{2})(1-2\sin^2 A \cos^2 A)\]

Answer 9

@Loser66 help me with the others as well....

Answer 10

@Loser66 thanks anyways i got the answers...