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Mathematics 21 Online
OpenStudy (anonymous):

Create your own quadratic equation that has an axis of symmetry of x = 1 and whose graph opens down. Then find the vertex, domain, range, and x-intercepts. Show all work to receive full credit.

OpenStudy (anonymous):

@AravindG

OpenStudy (aravindg):

-b/2a =1

OpenStudy (aravindg):

a<0

OpenStudy (anonymous):

Thx. Is that answer Algebra 1?

OpenStudy (anonymous):

Which one is it?

OpenStudy (anonymous):

we could translate the graph of x^2 to the right in this way (x-1)^2 and then invert the graph so it opens downward y=-(x-1)^2

OpenStudy (anonymous):

What do you mean?

OpenStudy (anonymous):

????

OpenStudy (anonymous):

What would the answer be? Simply put.

OpenStudy (anonymous):

@julian25 you kind of abandoned me here!

OpenStudy (anonymous):

so u need just the answer? and in the test? what u ill do? well i already told u the answer y=- (x-1)^2

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