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Create your own quadratic equation that has an axis of symmetry of x = 1 and whose graph opens down. Then find the vertex, domain, range, and x-intercepts. Show all work to receive full credit.
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@AravindG
-b/2a =1
a<0
Thx. Is that answer Algebra 1?
Which one is it?
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we could translate the graph of x^2 to the right in this way (x-1)^2 and then invert the graph so it opens downward y=-(x-1)^2
What do you mean?
????
What would the answer be? Simply put.
@julian25 you kind of abandoned me here!
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so u need just the answer? and in the test? what u ill do? well i already told u the answer y=- (x-1)^2
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