Question

if you have a parametric equation like r=6/(5+5sin(theta)), you get points (6/5,0), (6/10,pi/2),(6/5,pi), and this weird one (undefined, 3pi/2)...what on earth do you do when a point is undefined?

Answer 1

so at angle 3pi/2 or even at -pi/2, r becomes undefined...so do you just not plot that point or what? You can look at this graph if it can maybe help you make me understand better... http://www.wolframalpha.com/input/?i=r%3D6%2F%285%2B5sin%28theta%29%29
from the looks of the graph, if r is every undefined, it looks like you just simply do not plot anything...is that correct?

Answer 2

when you have an undefined value, you'll have either a removable point discontinuity, a jump discontinuity or an asymptote