2x^2/x^2-1
What are the intercepts? Where is it increasing/deacreasing? Local max/local min? describe the concavity? And what are the inflection points.

Question

2x^2/x^2-1
What are the intercepts? Where is it increasing/deacreasing? Local max/local min? describe the concavity? And what are the inflection points.

anonymous · Answer

$$2x ^{2}\div x ^{2}-1$$

anonymous · Answer

this was on my final, i was there literarily an hour trying to figure this out.

anonymous · Answer

did you have a graphing calculator?

anonymous · Answer

no calcs where allowed in the class

anonymous · Answer

i kept thinking since it was divived by x^2 that it might of been a straight line, but i was wrong.

anonymous · Answer

ok. to find y-intercept, make x=0
to find x-intercept, make y=0
to find local max/min, take the derivative and set it =0
to find concavity, take the second derivative
to find inflection points, set the second derivative =0

anonymous · Answer

i knew all that, i just kept getting 0 for all of my answers

anonymous · Answer

sketching the graph also helps

anonymous · Answer

because if you divide by your denominator, you get 2x^2=0 then

anonymous · Answer

So intercept is y=0, x=0. Now compute the limits when x tends to +- infinity and when x tends to 0 from the left and from the right. Doing that you will know the asymptotes.