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lim x→-2 x+2/√(x^2-4)
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@Loser66 what's the l'hopital rule?
do i multiply both of them by √(x^2 +2)
@Loser66 i don't know what derivative means
oop, you study limit and not know about derivative? ok, I take it back and think other way, hihi, sorry for that
@Loser66 i don't pay attention in class
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sorry friend, I really don't know how to solve without applying l'hopital rule. wait for other 's help,
\[\begin{align*}\lim_{x\to-2}\frac{x+2}{\sqrt{x^2-4}}&=\lim_{x\to-2}\frac{x+2}{\sqrt{(x+2)(x-2)}}\\ &=\lim_{x\to-2}\frac{x+2}{\sqrt{x+2}\sqrt{x-2}}\\ &=\lim_{x\to-2}\frac{\sqrt{x+2}}{\sqrt{x-2}}\\ \end{align*}\]
@SithsAndGiggles would i plug in the -2 for the x next
Yes.
@SithsAndGiggles thanks
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