Question

I dont understand how you get from one step to another. . . has to do with differential equasions

Answer 1

\[u-70=e ^{\ln(u-70)} = e ^{kt+C} = e ^{C}e ^{kt}\]

Answer 2

ln(u-70) + kt+C

Answer 3

theyre in reverse order

Answer 4

@timo86m

Answer 5

@bahrom7893

Answer 6

u-7 = u-70

well it simpliifies to this. by using the exponent properties right?

Answer 7

i think. . . i'm not sure

Answer 8

I am sure :)