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The proof by indirect method is shown below. In which step does the contradiction appear? Given: –→BD is not ⊥ ↔AC Prove: m∠1 ≠ m∠2 Step 1: Assume m∠1 = m∠2 Step 2: ∠1 and ∠2 are linear pairs and supplementary angles Step 3: ∠1 and ∠2 are right angles Step 4: –→BD ⊥ ↔AC Step 5: m∠1 ≠ m∠2 A. Step 1 B. Step 5 C. Step 2 D. Step 4
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|dw:1368112238970:dw|
U were right! :P sorry. Step 4
oh i got confused lol :)
It is GIVEN that it is NOT perpendicular, so in the proof they cannot say they are.
More? :D
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thanks again :)
yes!
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