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A fair coin is tossed three times. What is the probability of obtaining one Head and two Tails?
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First, there are in totality \(2^3 = 8\) different kinds of outcomes. Now you have to find the number of ways that you could arrange one head and two tails.
it is 3so the probability is 3/8 but my question is tossing a coin is one independent even
so the probability of get a head is 1/2 and a tail is 1/2 so why the probability is not (1/2)(1/2)(1/2) ?
The probability is not (1/2)(1/2)(1/2) because it is not given that we have to find the probability of HTT. But we have to find the probability of getting two tails and a head, which can happen in these ways as well: THT HTT
oh! i got it
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thanks men
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