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Mathematics 8 Online
OpenStudy (anonymous):

MATH HELP! MEDALS WILL BE GIVEN !

OpenStudy (anonymous):

OpenStudy (anonymous):

Yea?

OpenStudy (anonymous):

@jim_thompson5910

OpenStudy (anonymous):

@amistre64

OpenStudy (anonymous):

HELP ! Please

OpenStudy (anonymous):

@goformit100

jimthompson5910 (jim_thompson5910):

have a look at this unit circle http://www.regentsprep.org/Regents/math/algtrig/ATT5/600px-Unit_circle_angles_svg.jpg and tell me which angle you think makes tan(x) = sqrt(3) true

OpenStudy (anonymous):

Thats confusing ?

jimthompson5910 (jim_thompson5910):

have you seen the unit circle before

jimthompson5910 (jim_thompson5910):

if this is the first time, then I recommend studying it

OpenStudy (anonymous):

No this isnt my first time

jimthompson5910 (jim_thompson5910):

ok if you were to divide the y coordinate of the point at x = 30 degrees by the x coordinate, what do you get?

OpenStudy (anonymous):

Give you please give me an calculator so i can get the answer. My calculator went dead.

jimthompson5910 (jim_thompson5910):

you can use wolfram alpha http://www.wolframalpha.com/input/?i=arctan%28sqrt%283%29%29

OpenStudy (anonymous):

i got 120

jimthompson5910 (jim_thompson5910):

no the angle is between 0 and 90

jimthompson5910 (jim_thompson5910):

look on that page I sent you and look for the section "Conversion from radians to degrees:"

OpenStudy (anonymous):

I got it. It's 60

jimthompson5910 (jim_thompson5910):

yep

OpenStudy (anonymous):

Can you help me with 3 more

jimthompson5910 (jim_thompson5910):

sure

OpenStudy (anonymous):

OpenStudy (anonymous):

you there ?

jimthompson5910 (jim_thompson5910):

I would use this identity tan^2 = sec^2 - 1 so the equation turns into sec^2(theta) - 1 = (-3/2)*sec(theta) now let z = sec(theta) to get z^2 - 1 = (-3/2)*z 2z^2 - 2 = -3z 2z^2 + 3z - 2 = 0 Now solve for z and tell me what you get

OpenStudy (anonymous):

Will this give me my answser ?

jimthompson5910 (jim_thompson5910):

it will lead you up to it, so kinda

jimthompson5910 (jim_thompson5910):

tell me what you got for z

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