Question

what is the solution

Answer 1

@agent0smith

Answer 2

@MtMtx

Answer 3

Option C would be correct.

Answer 4

Do you know how to use the quadratic formula?

\[\huge x = \frac{ -b \pm \sqrt {b^2 - 4ac } }{ 2a }\]

Answer 5

\[1 \pm i \sqrt{9}\]

Answer 6

Guys, don't just post an answer, that's not going to help @ihavemathquestions understand the question

Answer 7

@Jas9420 and @MtMtx

Answer 8

Sorry, the procedure's so long. T_T

Answer 9

It's not that long.

ax^2+bx+c

here we have

0.5x^2 - x + 5

so a=0.5, b = -1, c = 5

Plug them into \[\huge x = \frac{ -b \pm \sqrt {b^2 - 4ac } }{ 2a }\]