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If f(x) = x2 - 1, find f(3). 5 2 8 -2 @eSpeX
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@jim_thompson5910
f(0)= 0^2 -1 f(1) = 1^2 -1 f(2) = 2^2-1 see the pattern?
Kind of, yes.
@mathslover ?
so the f(3) would be ?
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ummm f(3)= 2^3 -1?
f(3) = x2 - 1 then solve
All you're doing is replacing x with 3 f(x) = x^2 - 1 f(3) = 3^2 - 1 ... replace each copy of 'x' with 3 f(3) = ???
is it : \(f(x) = x^2 - 1\) ?
f(3) =8?
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yes
Thanks everyone!
Jim, has got the point correct. You just have to put x = 3 for \(f(3) \) For example : \(f(x) = x^2 - 1\\ f(1) = 1^2 - 1 \\ f(2) = 2^2 - 1 \\ f(3) = ?\)
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