Question

Express, in terms of x, the mean of (9x^2+7),
(4x-16), (8x-x^2) and (4x^2+9)

Answer 1

\[\frac{ (9x^2+7)+ (4x-16)+ (8x-x^2) +(4x^2+9)
}{4}\] is a start

Answer 2

combine like terms in the numerator, then divide by 4

Answer 3

i think the numerator is
\[12x^2+12x\]

Answer 4

when you divide by 4 you get \(3x^2+3x\)

Answer 5

Thanks alot!