Question

solving logarithm : How do I solve this?
-10 + log3 (n+3)=-10

Answer 1

Where you're not sure?

Answer 2

This is a problem that a friend of mine sent me, asking me for help. I know not how to solve this sort of problem.

Answer 3

So I thought that I could ask in here.

Answer 4

Ok, you can eliminate -10 by adding 10 both sides
\[-10 + \log_3 (n+3)=-10\]
\[\log_3(n+3)=0\]
Then use logarithm rule
\[\log_ba=c \leftarrow \rightarrow a=b^c\]

Answer 5

Thank you. :)

Answer 6

Welcome

Answer 7

This is what he sent me.
logba=c←→a=bc
?

Answer 8

So which one is ba and which one is c?

Answer 9

You can directly see it
a=n+3
b=3
c=0

Answer 10

Using \(\log_ba=c \leftarrow \rightarrow a=b^c\)
\[n+3=3^0 \\ \\ n+3=1 \\ \\ n=?\]

Answer 11

-2?

Answer 12

Thank you again.