Question

How to find the tangent vector and the normal vector of the of the curve: r(t)=(ln sec(t))i, (t)j, (e^t)k. with t less our equal to (-pi/2) and bigger or equal to (pi/2).

Answer 1

yes, tangent vector T = <r'(t)> , just take partial derivative of r(t)

Answer 2

and divide by the module of r(t), right?