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Evaluate the indicated integral
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u = square root x
u = \(\sqrt{x}\)
ok
so thats it?
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\[du = \frac{ 1 }{ 2 \sqrt{x} }dx\]
\[2 \int\limits e^udu=2e^u+C \]
He did a u substitution. Make sure to plug in u=sqrt(x) back into the equation at the end.
okay
@ajmayberry so 2e(sqrtx) + C ??
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Yes, that's the solution!
so its correct?
Yes. It is correct if you write 2e^(sqrtx) + C.
okay
okay
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