http://i.imgur.com/QSv3TsY.jpg I stuck in it
Welcome to OpenStudy! Let me look at your problem. c:
Thank you , i'm waiting
thats alot of questions, were are you stuck at?
That IS a lot of questions... on matrices too... not my forte, but let's see what I can do.... first, pick a question :)
i like 7 and 8 .... 7 is simple, if det(B) not= 0, its independant and a basis 8 is just solving; Bx = (3,0,3)
of course 9 is the simplest of all, just let B = what it says, lol
I stuck in 6 & 4
Sorry for my late , i was very busy 2 day
well then, 6 has you use the inverse you found in 5 ... what is your inverse from 5?
4 is the same idea, use the inverse that you found in 3, since you did not get stuck in 3
\[Mx=b~\to~x=M^{-1}b\]
inverses can be more easily determined using an augment rather than the cofactor matrixes ...
I don't undrstand it 😞
Any help 😫, 4& 6 linear system
What can i do 😰
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