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Mathematics 16 Online
OpenStudy (anonymous):

http://i.imgur.com/QSv3TsY.jpg I stuck in it

OpenStudy (anonymous):

Welcome to OpenStudy! Let me look at your problem. c:

OpenStudy (anonymous):

Thank you , i'm waiting

OpenStudy (amistre64):

thats alot of questions, were are you stuck at?

terenzreignz (terenzreignz):

That IS a lot of questions... on matrices too... not my forte, but let's see what I can do.... first, pick a question :)

OpenStudy (amistre64):

i like 7 and 8 .... 7 is simple, if det(B) not= 0, its independant and a basis 8 is just solving; Bx = (3,0,3)

OpenStudy (amistre64):

of course 9 is the simplest of all, just let B = what it says, lol

OpenStudy (anonymous):

I stuck in 6 & 4

OpenStudy (anonymous):

Sorry for my late , i was very busy 2 day

OpenStudy (amistre64):

well then, 6 has you use the inverse you found in 5 ... what is your inverse from 5?

OpenStudy (amistre64):

4 is the same idea, use the inverse that you found in 3, since you did not get stuck in 3

OpenStudy (amistre64):

\[Mx=b~\to~x=M^{-1}b\]

OpenStudy (amistre64):

inverses can be more easily determined using an augment rather than the cofactor matrixes ...

OpenStudy (anonymous):

I don't undrstand it 😞

OpenStudy (anonymous):

Any help 😫, 4& 6 linear system

OpenStudy (anonymous):

What can i do 😰

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