Question

Can someone please help me

Answer 1

tell me your problem

Answer 2

lets see

Answer 3

I got an answer of but I don't think it is right

Answer 4

that is supposed to say60

Answer 5

x+2y=120
2y=120-x
y=60-x/2

xy = x(60-x/2) = 60x -x^2/2
Let P= 60x-x^2/2
dP/dx = 60-2x/2
60-x=0
x=60

d^2P/dx^2 = -1 < 0, so P is maximum
Maximum value = 60(60) - (60)^2/2
3600-3600/2=1800

Answer 6

that help any?

Answer 7

yes so all I needed to do was go a little bit furether and I would have had 1800 as my final answer correct?

Answer 8

exactly, i'm glad I could help

Answer 9

thanks