how to solve (m+8)(m-2)=0
\[(m+8)(m-2)=0 \] explain how to please
One of those terms equals zero, because no non-zero numbers multiply to give zero. The solutions are given by setting each term equal to zero and solving the resulting simple equations.
I don't really remember F.O.I.L but I know that I can use it
You don't need FOIL, just set each term equal to zero and solve for m.
if I set each term to equal zero, I get two answers, do I just combine these answers so I'd get -6 ?
well?
No, each answer is a separate solution.
solve for m?
m= -8 m= 2
0 = m + 8 Solve. 0= m - 2 Solve.
\[(m+8)= 0 \] \[m = -8\] ------------------- \[(m-2)=0\] \[m = 2\]
alright
You got it? :)
yes
mm kay :))
can you also help me solve another one?
Ya, post a new question though :))
Please post separate questions. It saves scrolling and allows people to receive separate medals for both answers.
ok
Yuppers @Numb3r1 :))
@isaacme What the heck? :P
lol ikr
e.cciuba i use this rule deta=b²-4ac for solve kind of this equation ax+by+c =0
The tops correct, but wats w/ the last part?
lol no i use two ways.. just give him how to solve when be this formula ax²+by+c and will get the same answer. no faut : deta=b²-4ac=sqrt{100} \[m=\frac{ -6+\sqrt{100} }{ 2}=2 and m2=\frac{ -6-\sqrt{100} }{ 2}=8\]
mmm kay! :))
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