Question

1 + sec^2x sin^2x = sec^2x

Answer 1

prove?

Answer 2

yeah

Answer 3

\[sec^2 x= \frac{1}{cos^2 x}\] so plug there to get \[1+\frac{sin^2x}{cos^2 x}= 1 + tan^2 x = sec^2 x\]that 's it

Answer 4

thanks!

Answer 5

ok,