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find the integral of 27x-9/(3x^2-2x+1)^4dx
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i already know that my u is 3x^2-2x+1 and i already solved for that and i got du=6x-2dx
factor out 3, which leaves you with 3x-1, which can divide 27x-9
would it be something like 9/2 u^-3/-3 for the final part and just plug in the u or no
you have to return the u = whatever it was before
okay but is the final equation that i previously typed correct
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chill.........
no
hmm for the 6x-2 i can factor out a 2 and ill be left with 3x-1 and if i factor out a 9 from the 27x-9 i can also get 3x-1 right but im having trouble setting it up
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