Question

CA

Answer 1

A.










B.










C.










D.

Answer 2

a. -3+x
b.x-6
c.3x-6
d.3x+6

Answer 3

@RadEn

Answer 4

@lexiamee Do you know factorization?

Answer 5

I dont know how to figure this out

Answer 6

Let's factor
\[x^2-9x+18\]Can you try?

Answer 7

If you look well, there's the whole procedure. so dont be telling me that I just gave the answer

Answer 8

@Luis_Rivera you did not show how to factor neither you involved the asker in the solving process.

Answer 9

9=3*3
9*9=3*3*2

Answer 10

Have you learnt factorization? like the factors for
\[x^2+6x+9\]
are
\[(x+3)(x+3)\]
@lexiamee

Answer 11

oh okay

Answer 12

http://openstudy.com/users/luis_rivera#/updates/5161d670e4b06dc163b9e02f

Answer 13

@lexiamee \[x^2-6x+9\]
Tell me factors of 9, which add up to become -6

Answer 14

-3*2

Answer 15

\[x^2-9x+18\]
Sorry Factors of 18 @lexiamee
They should multiply to give 18
and sum to become -9

Answer 16

-3*3

Answer 17

Factors of 18 ??

Answer 18

3*3*2

Answer 19

You're right, but they should sum to become -9

Does -6 and -3 are the required factors?

Answer 20

-6*-3=18

Answer 21

does they add to become -9?

Answer 22

no

Answer 23

-6 + -3
-6-3=-9

Answer 24

okay

Answer 25

so let's write -9x as -6x -3x
\[x^2-6x-3x+18\]
can you take out x from the first two terms?

Answer 26

what ones ?

Answer 27

\[\underline{x^2-6x}-3x+18\]

Answer 28

^2 - 6

Answer 29

?

Answer 30

\[x^2-6x=x (x-6)\]

Answer 31

yeah