Question

i give medals and fans

Answer 1

\[x^2 – 7x = –13\]

Answer 2

ok lets see

Answer 3

x^2 - 7x + 13 = 0
a = 1, b = - 7,c = 13
- - 7 +/- Sqrt(49 - 4*1*13) / 2
7 +/- Sqrt49 - 52) / 2
7 +/- Sqrt -3 / 2
x = 1/2(7 - iSqrt3)
x = 1/2(7 + iSqrt3)
Ans D
and that's the end XD

Answer 4

u got it?

Answer 5

not really

Answer 6

what would you like me to explain a bit better?

Answer 7

ok Add 13 to both sides
x^2-7x+13=0
2. Use the quadratic formula: x=(-b+-sqrt(b^2-(4ac)))/2a
ax^2+bx+c
x=(7+-sqrt(49-52))/2
you get the square root of a negative number, which means that there are no real solutions to this equation.

Answer 8

kk

Answer 9

but if you need an answer Put in the form ax^2 + bx + c = 0

So:
x^2 - 7x + 13 = 0

Apply the quadratic equation
x = (-b (+ or -) sqrt(b^2 - 4(a)(c)))/(2*a)

Your answer is
x = (7 +or- i*sqrt(3))/2

Answer 10

done deal if you need any more help pm me