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Mathematics
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Operations w/ Radicals
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\[ simplify \sqrt{32x}+7\sqrt{12x}+\sqrt{98x}\]
\[11\sqrt{2x}+14\sqrt{3x}\]
\[\sqrt{16*2x}=4\sqrt{2x}\\ \sqrt{12x}=4\sqrt{3x}\\ \sqrt{49*2x}=7\sqrt{2x} \\ Now\ \ add \ \ them\]
dont forget the 7 attached to the 12x lol. My answer is right .-.
\[7\sqrt{12x} = 7(2)\sqrt{3x} = 14\sqrt{3x}\]
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lol thats not right..
there is a 7 in frnt of 12x. Look at the problem
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