Question

Factor the polynomial completely.
6x^2 - 19x + 13

Answer 1

i hate factoring

Answer 2

try \((x-1)(6x-13)\)

Answer 3

well start by multiplying 6 by 13

6 * 13 = 78

find the factors of 78 that add to - 19

they are both negative...

one of then is -6, whats the other...?

Answer 4

multiply outside coefficients ..... 6*13 = 78

now try to find 2 factors of 78 that add up to -19
-6 + -13 = -19
-6 * -19 = 78

now once you have found 2 factors that work, you can use factor by grouping or there is a shortcut method
bring down the first coefficient, then reduce any common factors
\[\rightarrow (6x-6)(6x-13)\]
\[\rightarrow (x-1)(6x-13)\]

Answer 5

sorry @campbell_st , didn't see your post

Answer 6

thats fine...@dumbcow

just so people can see what you cancel I always include the steps

(6x - 6)(6x - 13) 6(x -1)(6x -13)
-------------- = ----------------
6 6

cancel the common factor.