Question

what is the center of the circle given by the equation (x-2)^2+(y+4)^2=6? Wouldnt i have to use the pythagorean thereom or am i wrong?

Answer 1

or the circle formula

Answer 2

The circle formula: (x - h)^2 + (y - k)^2 = r^2

The center would be (h, k) with radius of r.

Answer 3

So, here you have h = 2 and k = -4 and r = sqrt(6)

Answer 4

All good now, @anonomyous ?

Answer 5

yes thank you

Answer 6

Don't forget to hit "best response"! Thanks in advance! @anonomyous