For the following system, if you isolated x in the second equation to use the Substitution Method, what expression would you substitute into the first equation?
2x + y = 8
-x - 3y = -12
3y + 12
-3y + 12
3y - 12
-3y - 12
@jim_thompson5910
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jimthompson5910 (jim_thompson5910):
solve
-x - 3y = -12
for x
OpenStudy (anonymous):
Where would I multiply that into
jimthompson5910 (jim_thompson5910):
you just need to isolate x (ie get it on one side)
OpenStudy (anonymous):
Divide -12 by 3y?
jimthompson5910 (jim_thompson5910):
no
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OpenStudy (anonymous):
Or er.. by -3y?
jimthompson5910 (jim_thompson5910):
you need to move over the -3y, but you don't divide
OpenStudy (anonymous):
I don't know how I'd do that >. <
jimthompson5910 (jim_thompson5910):
what undoes -3y
OpenStudy (anonymous):
Add?
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jimthompson5910 (jim_thompson5910):
yep, add 3y to both sides
OpenStudy (anonymous):
-x = -15 ?
OpenStudy (anonymous):
I think I did that wrong.
jimthompson5910 (jim_thompson5910):
no you don't add 3y to -12 to get -15y
jimthompson5910 (jim_thompson5910):
you just leave it as
-x = 3y - 12
so,
x = ??
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OpenStudy (anonymous):
I still don't understand.
jimthompson5910 (jim_thompson5910):
-x = 3y - 12
x = -3y + 12 ...multiply everything by -1
jimthompson5910 (jim_thompson5910):
so the answer is
-3y + 12
OpenStudy (anonymous):
Why did you multiply by -1? Just curious so I can understand what you did.
jimthompson5910 (jim_thompson5910):
well we had -x = 3y - 12
but we want x = ....
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jimthompson5910 (jim_thompson5910):
to go from -x to x, you multiply that -x by -1 to get x
jimthompson5910 (jim_thompson5910):
you have to multiply everything by -1 to balance things out