Question

I am not sure how to work out these equations...
sqrt(4x-7)=3-x

Answer 1

square both sides as step one, to get rid of the radical on the left

Answer 2

\[\sqrt{4x-7}=3-x\]
\[\sqrt{4x-7}^2=(3-x)^2\]
\[4x-7=9-6x+x^2\] (dont forget how to square correctly \((3-x)^2=(3-x)(3-x)=9-3x-3x+x^2=9-6x+x^2\)

Answer 3

your next job is to solve
\[4x-7=9-6x+x^2\] do you know how to do that?