Question

find the slope between x=0 and x=3, for the function: -sq(2x^2 -x +4)

Answer 1

\[-\sqrt{2x ^{2} - x +4}\]

Answer 2

@satellite73 has this question meaning to u?

Answer 3

Is the wording confusing?

Answer 4

Find the average rate of change of the function f over the given interval
x = 0 to x = 3
for the above function

Answer 5

yes it is i dont know what the problem ask
i think it must be
find the slope at the point x=3

Answer 6

ahhhh!!!!

Answer 7

it means
\[\frac{f(3)-f(0)}{3-0}\]

Answer 8

you got it from there?

Answer 9

right, could you please do it out for me? the answer they're giving is -3.4801

Answer 10

and I'm getting -.07863, and I don't know why

Answer 11

\[f(0)=-\sqrt{4}=-2\] right?

Answer 12

and \(f(3)=-\sqrt{19}\) i think

Answer 13

yes

Answer 14

so my answer would be
\[\frac{-\sqrt{19}+2}{3}\]

Answer 15

i have no idea what this looks like as a decimal, but i could check

Answer 16

ok, that's the same as mine! thank you, I was worried I was doing it wrong

Answer 17

yw