Question

Given: y=4x^3 - ln(3x+2)
Find: y'(1)

Answer 1

@phi

Answer 2

@RadEn

Answer 3

@satellite73

Answer 4

do you know what's the derivative of 4x^3 = ...
also the derivative of ln(3x+2) = ...

Answer 5

y'=12x^3 - 1/(3x+2) ?

Answer 6

-3/(3x+2)?

Answer 7

12x^3 or 12x^2 ?
the rest is okay :)

Answer 8

12x^2

Answer 9

so the answer is 57/5?

Answer 10

so, you have
y'=12x^2 - 3/(3x+2)
put x=1 to y'
y'(x=1) = 12(1)^2 - 3/(3*1+2) = 12 - 3/5 = 57/5

you are right ;)

Answer 11

but the answer at the back was 11 2/5

Answer 12

that's same :)

11 2/5 is just mix fraction of ... :P

Answer 13

ok, can you help me with another please? ^^

Answer 14

sure if i can :)