Question

Can you help me solve this equation ?

2x^3-3x^2-36x+5

Answer 1

Solve for x? Like find the roots?

Answer 2

Maybe if you can trial an error by using a calculator and plugin for x=-5,-4,-3....3,4,5
See if it gives zero

Answer 3

I tried I can find any number that does the trick

Answer 4

can't*

Answer 5

Maybe f(5) ?

Answer 6

5 does it?

Answer 7

Yeah,
f(5)=2(5)^3-3(5)^2-36(5)+5

Answer 8

So it'll be
(x-5)(.....)

Answer 9

(x-5)(Quadratic)

Answer 10

There are 3 answers, 5 is one of them. The others are irrational numbers being: -3.637... and 0.137...

Answer 11

I worked out, (x-5)(2x^2+7x-1)
So use quadratic formula for 2x^2+7x-1 find the roots

Answer 12

thank you

Answer 13

Why my result is (x-5)(2x^2-3x-36) ?

Answer 14

@.Sam.

Answer 15

Maybe you factored it incorrectly, if you expand it you should get back the original equation

Answer 16

Can you help me please with the long division @.Sam. ?

Answer 17

I am sorry to say. I didnt understand anything. No offence !