Question

which point lies on the line defined by 3x+6y=2?

Answer 1

to check just u pug the values of the point in place of x and y and if it satisfies the equation then it lies on the line otherwise it doesn't

Answer 2

Just put it in y = mx + b form

Subtract 3x over
6y = -3x + 2

Divide 6
y = -(1/2)x + 1/3

b is the y intercept (when x = 0).
y = 1/3

When y = 0
Just use one of the above steps and plug in 0 for y,
I'm going to use 6y = -3x + 2
0 = -3x+2

Simplify and solve for x

3x = 2

x = 2/3

So the points are (2/3, 0) and (0, 1/3) lie on the line.

Answer 3

:) That's actually too much work. Just do what @matricked said. I'm going to leave my answer in case it's any use for you.

Plug in random value for x and whatever y equals, that is a point on the line.