Question

multiply ...

Answer 1

\[\frac{ k+3 }{ 4k-2 }\times \left( 12k ^{2} +2k-4\right)\]

Answer 2

Try to factorise 12k^2+2k-4 and tell me vat u get

Answer 3

no clue

Answer 4

i am no good at this stuff

Answer 5

well can u tell me two factors of -48 such that their sum is 2?

Answer 6

-8 and 6

Answer 7

well it is other way round. i mean the numbers are 8 and -6.
Nw
2x can be written as 8x-6x. agree?

Answer 8

sure

Answer 9

\(12k^2+2k-4=12k^2+8k-6k-4\).
Nw can u factorise
\(12k^2+2k\)?

Answer 10

still dont get it

Answer 11

\(12k^2+2k=(2*6*k*k)+(2*k)\)
What is common to both \(12k^2 and 2k\)?

Answer 12

1 and 2 ?

Answer 13

2k is common

Answer 14

ok

Answer 15

take it out. then what remains?

Answer 16

\[12k ^{2}\]