ALGEBRA 2 HELP! If sin 0 = sqrt3/2, which could not be the value of 0?
you mean theta? 0 with a horizontal line?
use this unit circle http://www.regentsprep.org/Regents/math/algtrig/ATT5/600px-Unit_circle_angles_svg.jpg
a negative
yes @primeralph
Ohhhh 0 is just theta xD That confused me for a minute. When we are dealing with sin, we are working with the y coordinates. So use the unit circle that jim posted and find a y coordinate that matches sqrt(3/2).
Oops, you actually wrote (sqrt3)/2, look for that one >.<
here are the multiple choice answers 60 degrees 120 degrees 240 degrees 420 degrees
The degrees are listed on the chart too. The chart shows that it is 60 degrees, since at 60 degrees the y value is (sqrt3)/2
so as smokeydabear is saying, sin(60) = sqrt(3)/2 so that eliminates 60 as a possible answer
Ok...
Oh derp, we are finding what it CAN'T be, I'm sorry! >.< Then yes it isn't 60 degrees.
yeah they throw those tricks in to make sure you're still awake
haha @jim_thompson5910
Which is why you should always get plenty of rest before exams! Which I never do ._.
...that's of course if math hasn't bored you to sleep already hopefully that's not the case
yes, definitely a good idea smokeydabear
Well I have to go I will be back a little later. Thanks though.
Have to admit, it does get really tedious after a while, but not at this stage, so keep plowing forward Sue! Do you understand how we determined the above?
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