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Algebra
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Sam has a total of 58 DVDs and CDs. If the number of CDs is two more than three times the number of DVDs how many CDs does he have?
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no of cds:44 no of dvds:14
Let the number of DVDs be d and the number of CDs be c. c+d=58 c=2+3d Solve for c and d.
and how do you do that?
Substitute c=2+3d. Then you can work out d. And then substitute d into c=2+3d.
I still don't understand
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I know your supposed to move something around but what?
Now you have two equations: c+d=58 c=2+3d If you substitute c=2+3d into c+d=58, then the first equation will be like: 2+3d+d=58, which is 4d=58-2=56 So d=56/4=14
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