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Find f‘(x) given the integral function f(x)
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du
@myko can u help?
And if you integrate 2u-3, with respect to u, what do you get?
hmm i get (x - 3) x
Umm.. Just take the integral of (2u-3)du, what does that give you?
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ohh okay u^2 - 3u + C
Right, so now you just replace the 'u' with your limits and subtract the lower from the upper.
ohh okay thanks
You're welcome.
i got -x^2 - 3x is that correct?
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Not sure where you got the -x^2 from, but in general it is.
\[(x^{2}-3x)-(0^{2}-3(0)) \rightarrow x^{2}-3x+c\]
ohh ok i see where i made my mistake
Excellent, good luck.
ohh ok i see where i made my mistake
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