(12x^2 + 9x – 7) ÷ 3x Help, I don't understand.
Wow i need help on the same exact question...
\[\frac{12x^{2}+9x-7}{3x}\rightarrow \frac{12x^{2}}{3x}+\frac{9x}{3x}-\frac{7}{3x}\] and simplify.
Thank you, though I'm still not sure I understand.
What is it that you are asked to do with this question?
It simply says to multiply or divide. This is division, though I'm not understand how you got to your conclusion or how to reduce further.
Are you familiar with fractions?
Somewhat, I haven't had to do them for a few years now. I think to simplify you see what factors the numerator and denominator have until you reach the point where it can't reduce anymore.
Basically, yes.
So how many times can 3x go into 12x^2?
Thank You @eSpeX
Umm. You're welcome @Justin_Bieber1994 :D
3 goes into 12 four times, though I don't know what to do with the square. or erm. ^2 that.
What happens if you multiply x*x?
You either get 0 or 1..I forget..
\[2*2=4,\rightarrow 4=2^2\] The same thing applies with 'x'
So,\[3x*4x=12x^2\]
Okay, I'm still unsure as of how to apply that to answer my equation...
What do you get when you divide your 12x^2 by 3x?
4x
Exactly, you have just reduced the first term. :)
How about the second one \[\frac{9x}{3x}\]
3x, but does the ^2 carry over with the four?
No, you treat each term individually. You are done with the first term, it reduces to 4x, now just worry about the second term. What times 3x = 9x?
3x
3x*3x=9x^2
3?
Very good, now you have the first two terms completed. What can you do with the last term?
I don't know. 7 doesn't go into three and three doesn't go into 7.
Exactly, so there is nothing you can do with that. So your resulting expression is what?
4x, 3 and 7/3x
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