Quadratic equation help: x^2-5x-6=0

how is the (1/2b)^2 supposed to work out in this equation?

Question

Quadratic equation help: x^2-5x-6=0

how is the (1/2b)^2 supposed to work out in this equation?

abb0t · Answer

The quadratic equation is defined as $\huge x = \frac{-b \pm \sqrt{b^2-4ac}}{2a}$
when given: $\large ax^2+bx+c$

anonymous · Answer

the ( 1/2) ^2  is only used for completing the square

abb0t · Answer

@Luis_Rivera that's the homegirl!!!! help a nikkuh out!!

anonymous · Answer

I have no idea, my teacher has a weird way of teaching. His rules to follow are: divide to make first coeffecient =1, 1/2b)^2 for complete square, eliminate fractions, factor left/simplify right, followed by square root prop. :3

anonymous · Answer

i knew it !!

abb0t · Answer

are you solving for $\large "x"$ ?

abb0t · Answer

@UnkleRhaukus

anonymous · Answer

|dw:1368518803337:dw|