Circles M and K are congruent, QR is congruent to LN and OP is congruent to VW. Find x.
Answers:
-9
-11
-6
-3
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OpenStudy (anonymous):
OpenStudy (ddcamp):
Using OP congruent to VW:
\[-6x = -6y + 18 \rightarrow x = y - 3\]
Then QR being congruent to LN:
\[-2x = -3y + 3 \rightarrow -2(y-3) = -3y + 3 \rightarrow -2y + 6 = -3y + 3 \rightarrow y = -3\]
And plugging that into the first equation:
\[-6x = -6(-3) + 18 \rightarrow -6x = 36 \rightarrow x = -6\]
OpenStudy (anonymous):
Wow, thank you if x is -6 then y would be...?
OpenStudy (ddcamp):
-3 (see the second line of equations)
OpenStudy (anonymous):
Awesome could you help me out with a few more?
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OpenStudy (anonymous):
AB and BC are tangent to circle D. Find x if AB = x + 15 and BC = 2x – 5. Find x.
Answers:
18
21
19
20
OpenStudy (anonymous):
OpenStudy (ddcamp):
AB and BC are congruent, so x+15 = 2x-5
OpenStudy (anonymous):
Would that be 20?
OpenStudy (ddcamp):
yup
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OpenStudy (anonymous):
Ok 2 more
OpenStudy (anonymous):
Find x .
Answers:
112
154
101
110
OpenStudy (anonymous):
OpenStudy (ddcamp):
Angle AED is going to be 116°, AEB and DEC are 64°. Other than that, I don't know what to say.
OpenStudy (anonymous):
You cant find x?
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OpenStudy (anonymous):
No worries tho can you figure out this one then?
Find angle A if DE is equal to 50 and BC is equal to 10
Answers:
30
20
40
50
OpenStudy (anonymous):
@DDCamp
OpenStudy (anonymous):
@ganeshie8
ganeshie8 (ganeshie8):
use this :-
outside angle = (far arc - near arc)/2
ganeshie8 (ganeshie8):
do you knw how to make out, what far arc and near arc are ?
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OpenStudy (anonymous):
yes I got 40?
ganeshie8 (ganeshie8):
divide it by 2
OpenStudy (anonymous):
20 is the answer
OpenStudy (anonymous):
Could you help with the question prior me or DDCamp can solve it? @ganeshie8
OpenStudy (anonymous):
Find x .
Answers:
112
154
101
110
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ganeshie8 (ganeshie8):
so you wanto find arc BC
OpenStudy (anonymous):
no X @ganeshie8
ganeshie8 (ganeshie8):
x = arc BC = central angle BC
OpenStudy (anonymous):
Oh then yes how do I find?
ganeshie8 (ganeshie8):
lets look at whats given.
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ganeshie8 (ganeshie8):
we're given arc AD = 78
so, inscribed angle DBA = ?
OpenStudy (anonymous):
156?
ganeshie8 (ganeshie8):
good guess, but no
ganeshie8 (ganeshie8):
OpenStudy (anonymous):
39
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ganeshie8 (ganeshie8):
yes, DBA = 39 --------------------(1)
ganeshie8 (ganeshie8):
now lets look at whats given again
ganeshie8 (ganeshie8):
we're given angle BEC = 116.
look at pic carefully,
BEC is the exterior angle in triangle AEB. so it equals to the sum of its remote angles :-
BEC = B + A
116 = 39 + A
A = ?
OpenStudy (anonymous):
A=77 @ganeshie8
ganeshie8 (ganeshie8):
yes,
A = 77
but we need to find x
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ganeshie8 (ganeshie8):
look at pic again,
A is the inscribed angle of central angle x.
use this relation :-
central angle = inscribed angle * 2
ganeshie8 (ganeshie8):
x = A*2
= 77*2
OpenStudy (anonymous):
154?
ganeshie8 (ganeshie8):
yep!
OpenStudy (anonymous):
Thank you so much!
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