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Mathematics 7 Online
OpenStudy (anonymous):

Circles M and K are congruent, QR is congruent to LN and OP is congruent to VW. Find x. Answers: -9 -11 -6 -3

OpenStudy (anonymous):

OpenStudy (ddcamp):

Using OP congruent to VW: \[-6x = -6y + 18 \rightarrow x = y - 3\] Then QR being congruent to LN: \[-2x = -3y + 3 \rightarrow -2(y-3) = -3y + 3 \rightarrow -2y + 6 = -3y + 3 \rightarrow y = -3\] And plugging that into the first equation: \[-6x = -6(-3) + 18 \rightarrow -6x = 36 \rightarrow x = -6\]

OpenStudy (anonymous):

Wow, thank you if x is -6 then y would be...?

OpenStudy (ddcamp):

-3 (see the second line of equations)

OpenStudy (anonymous):

Awesome could you help me out with a few more?

OpenStudy (anonymous):

AB and BC are tangent to circle D. Find x if AB = x + 15 and BC = 2x – 5. Find x. Answers: 18 21 19 20

OpenStudy (anonymous):

OpenStudy (ddcamp):

AB and BC are congruent, so x+15 = 2x-5

OpenStudy (anonymous):

Would that be 20?

OpenStudy (ddcamp):

yup

OpenStudy (anonymous):

Ok 2 more

OpenStudy (anonymous):

Find x . Answers: 112 154 101 110

OpenStudy (anonymous):

OpenStudy (ddcamp):

Angle AED is going to be 116°, AEB and DEC are 64°. Other than that, I don't know what to say.

OpenStudy (anonymous):

You cant find x?

OpenStudy (anonymous):

No worries tho can you figure out this one then? Find angle A if DE is equal to 50 and BC is equal to 10 Answers: 30 20 40 50

OpenStudy (anonymous):

@DDCamp

OpenStudy (anonymous):

@ganeshie8

ganeshie8 (ganeshie8):

use this :- outside angle = (far arc - near arc)/2

ganeshie8 (ganeshie8):

do you knw how to make out, what far arc and near arc are ?

OpenStudy (anonymous):

yes I got 40?

ganeshie8 (ganeshie8):

divide it by 2

OpenStudy (anonymous):

20 is the answer

OpenStudy (anonymous):

Could you help with the question prior me or DDCamp can solve it? @ganeshie8

OpenStudy (anonymous):

Find x . Answers: 112 154 101 110

ganeshie8 (ganeshie8):

so you wanto find arc BC

OpenStudy (anonymous):

no X @ganeshie8

ganeshie8 (ganeshie8):

x = arc BC = central angle BC

OpenStudy (anonymous):

Oh then yes how do I find?

ganeshie8 (ganeshie8):

lets look at whats given.

ganeshie8 (ganeshie8):

we're given arc AD = 78 so, inscribed angle DBA = ?

OpenStudy (anonymous):

156?

ganeshie8 (ganeshie8):

good guess, but no

ganeshie8 (ganeshie8):

OpenStudy (anonymous):

39

ganeshie8 (ganeshie8):

yes, DBA = 39 --------------------(1)

ganeshie8 (ganeshie8):

now lets look at whats given again

ganeshie8 (ganeshie8):

we're given angle BEC = 116. look at pic carefully, BEC is the exterior angle in triangle AEB. so it equals to the sum of its remote angles :- BEC = B + A 116 = 39 + A A = ?

OpenStudy (anonymous):

A=77 @ganeshie8

ganeshie8 (ganeshie8):

yes, A = 77 but we need to find x

ganeshie8 (ganeshie8):

look at pic again, A is the inscribed angle of central angle x. use this relation :- central angle = inscribed angle * 2

ganeshie8 (ganeshie8):

x = A*2 = 77*2

OpenStudy (anonymous):

154?

ganeshie8 (ganeshie8):

yep!

OpenStudy (anonymous):

Thank you so much!

ganeshie8 (ganeshie8):

np

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