Question

how to solve it

Answer 1

Check the equation again ,there is something wrong .

Answer 2

oh yes it 5x^2

Answer 3

guys check out my question

Answer 4

Are you familiar with grouping factoring ?

Answer 5

yes

Answer 6

Good ,So your equation is \[\Large 2x^4-3x^3-5x^2+9x-3=0\]
Using Group factoring you will get :
\[\Large (x-1)(2x-1)(x^2-3)=0\]
Solve each term separately ..
Can you continue?.

Answer 7

yes
x=1
x=1/2
x=+-root3

Answer 8

Good job

Answer 9

but here we have to find it another way

Answer 10

hmmm ,u mean in an alternative form or something ?
well ,there is an alternative form for it
Like :
\[\Large 2x^4-3x^3-5x^2+9x-3=0\]
\[\Large 2x^4+9x=3x^3+5x^2+3 \]
And factorize and solve ..
you will get the same answers

Answer 11

@eyad
thanks bro
i got it

Answer 12

yw anytime :)