Ask your own question, for FREE!
Mathematics 16 Online
OpenStudy (anonymous):

plse friends, help me to solve this

OpenStudy (amistre64):

i still think a contradication is the best setup assume that AnB = AnC, and show that B not= C is a contradiction let x be a general element in AnB x in A and x in B since AnB = AnC, then x is an element of AnC x in A and x in C but x in B and x in C contradicts B not= C

OpenStudy (amistre64):

the second part should run the same sort of course

OpenStudy (amistre64):

let x in B, x not in A x in AuB since AuB = AuC, then x in AuC; but since x not in A, then x in C x in B and x in C contradicts B not= C

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!