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Use the figure below: 5) If <1 is congruent to <2, what postulate can you use to prove that the triangles ABC and EBD are similar?
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|dw:1368636993179:dw|
<1 = <2 Given <b = <b Vertical Angles Theorem ABC = DEB AA~ Postulate
6) In the diagram below of right triangle ACB, altitude intersects at D. If AD=3 and DB=4, find the length of BC in simplest radical form.
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|dw:1368638943106:dw| just some extra work
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if angles of triangle ABC = Angles of triangle EBD Then triangle ABC similar EBD. |dw:1368643022656:dw| In triangles ABC & EDF \[<2=<1 \left( given \right)\] <3=<4 (vertical opposite angles) <5=<6 ( third angle of the triangle) Hence triangle ABC similar to triangle EBD
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