Suppose a normal distribution has a mean of 38 and a standard deviation of 2. What is the probability that a data value is between 37 and 41? Round your answer to the nearest tenth of a percent. A. 83.5% B. 77.5% C. 56.5% D. 62.5%
i wanna say that 62 is the most reasonable to me
thank you,did you get my message ?
yeah
what do you think
post them up and lets see what we can do
If a normal distribution has a mean of 44 and a standard deviation of 8, what is the z-score for a value of 50? A. 0.75 B. 1.25 C. 1.75 D. 0.25
\[z=\frac{x-mean}{sd}\]
so where would i plug the 44 in
mean is 44 sd is 8 and x = 50
so i got 6/8
correct
which simplified is 3/4
which is .75 :D
If a normal distribution has a mean of 132 and a standard deviation of 20, what is the value that has a z-score of 3.6? A. 168 B. 180 C. 144 D. 204
which value is 3.6 sds from the mean? 132 + 3.6(20)
i got like 2000 something :(
try to hit the decimal ....
lol sorry i saw that its 204 ! are you a teacher ?
Which of the following expressions entered into a graphing calculator will return the probability that a data value in a normal distribution is between a z-score of -2.33 and a z-score of 0.17? A. normalcdf(-0.17, 2.33) B. normalcdf(0.17, 2.33) C. normalcdf(-2.33, 0.17) D. normalcdf(2.33, 0.17)
im an old person, im working on a masters in math tho
I hope you get it,your very smart
the normalCDF functionon a ti83 takes the parameters: low, high, mean, sd
it defaults to mean=0 and sd=1
k you lost me :)
they give you 2 values to input .... one of them is lower in value than the other; how would you suggest we input them?
im sorry i dont know,these z-scores are gibberish to me :/
what are the zscores they give us?
-2.33 and 0.17
and the input into the normalCDF function is (low,high) would you agree that in this case, a negative value is always lower than a positive value?
yes ! :)
so armed with this vast assortment of low high trivia, do you see a best option? :)
so it would be a,-0.17 and 2.33 ?
im going to assume that is in jest ... and agree with C
haha your funny and make everything so simple !
If the mean of a normal distribution is 26, what is the median of the distribution? A. 18 B. 22 C. 14 D. 26
in a normal distribution, mean=mode=median
so it stays 26 ?
its a trick question ?
its a conceptual question :) they assume you know a normal distibution as equality among the central tendencies
hmmm translate please :)
and i just have 4 more if thats ok
the most observed value of the data is at the highest point the middle value (median), since its symmetric, is in the middle the mean of a symettric shape is the middle ... mean = mode = median
In a normal distribution, what percentage of the data falls within 1 standard deviation of the mean? A. 99.7% B. 34% C. 95% D. 68%
A and C are obvoius absurdities the question is, what do they mean by 1sd of the mean? ill assume they want 1 sd to each side of the mean and go with 68
sweet !
Suppose the heights of the members of a population follow a normal distribution. If the mean height of the population is 68 inches and the standard deviation is 4 inches, 99.7% of the population will have a height within which of the following ranges? A. 60 inches to 76 inches B. 56 inches to 80 inches C. 52 inches to 84 inches D. 64 inches to 72 inches
the emprical rule, 1-2-3 68-95-99 so take your mean and subtract 3sds for the lower limit take your mean and add 3sds for the upper limit
im confused again,about this whole thing and 3 sds and all that
sd is shorthand for standard deviation they give you the mean and the sd values
still kind of lost but im thinking d?
not d mean + 3(sd) they give you a mean of 68 and an sd of 4
ahhhh so b :)
b is better yes :)
Suppose a normal distribution has a mean of 98 and a standard deviation of 6. What is P(x 104)? A. 0.16 B. 0.84 C. 0.025 D. 0.975
is that x < 104?
yes
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