Question

what is the square for x^2-5x=10

Answer 1

do u know the answer for this ?

Answer 2

The roots?
First put it into standard form,
\[x^2-5x=10 \rightarrow x^2-5x-10 = 0\]
This isn't factor-able, so use the quadratic formula:
\[\frac{ -b \pm \sqrt{b^2 - 4ac} }{ 2a }\]
With a = 1, b = -5, c =-10
\[\frac{ 5 \pm \sqrt{5^2 - 4(1)(-10)} }{ 2(1) }\rightarrow \frac{ 5\pm \sqrt{65} }{ 2 }\]
Which doesn't simplify nicely, but is about 6.5311 and -1.5311