Question

Algebra 2 !!
Please HELP!

Answer 1

your drawing of the triangle is a little skewed. is it this?

Answer 2

Do you know how to find the hypotenuse using the pythagorean theorem?

Answer 3

a^2 +b^2 = c^2 right ?

Answer 4

yes , actually it would be easier if you remember \[(leg _{1})^{2} + (leg _{2})^{2} = (Hypotenuse)\]

Answer 5

Leg 1 and Leg 2 are the sides that form the right angle

Answer 6

Now go ahead and find the hypotenuse

Answer 7

Um i got 53 ! I dont think thats right!

Answer 8

Leg 1 = 5 and leg 2 = 12

5^2 = 25 and 12^2 = 144

so 25 + 144 = 169 = Hypotenuse ^2

Hypotenuse = Sqrt (169) = 13

Answer 9

You need to show me your work then I will know where you are going wrong and I can help you better

Answer 10

You have done only half of the problem. We still have the rest to do right?

Answer 11

right !

Answer 12

When i go find sin tan and cos i only find it for side A Correct?

Answer 13

Now you know all 3 sides. Just use the following formulas for finding the sin, cos and tan

\[\sin \theta = \frac{ Opposite \space side }{ Hypotenuse }\]

So for angle A opposite side is 12 and hypotenuse is 13. So SinA = 12/13

Similarly use the following to find Cos A and Tan A

\[\cos \theta = \frac{ Adjacent \space Side }{ Hypotenuse }\]
\[\tan \theta = \frac{ Opposite \space Side }{ Adjacent \space Side }\]

Answer 14

Okay ! Thanks (: