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Two cubes are tossed. Find P(only one shows a 2).
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I'm assuming you're talking about normal dice.
P(A die has a 2) AND P(A die doesn't have a 2) If you know each probability, you can find the overall probability.
You must evaluate the odds that one shows a two and the other doesn't, but the easiest way for this one is just to think about how many options fit the conditions.
Remember, the probability of event A and B happening is the product of P(A) and P(B).
i think it is a binomial probability where probability os suscess = 1/6 probability of failure = 5/6 so the answer is C(2,1)*(1/6)*(5/6)
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Correct.
Thank you :) Final answer is 5/18
Also correct!
I wish I could give you both medals.
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